182
edits
Talk:Headshot: Difference between revisions
→What the hell is this supposed to mean?
| Line 29: | Line 29: | ||
"In Halo: Reach, the damage system has been altered where damage applied on a shielded enemy would result in a headshot. In order to successfully produce a headshot, the player has to eliminate the enemy's shield, though the only exception to this would be the sniper rifle." | "In Halo: Reach, the damage system has been altered where damage applied on a shielded enemy would result in a headshot. In order to successfully produce a headshot, the player has to eliminate the enemy's shield, though the only exception to this would be the sniper rifle." | ||
I thought this is the system which ALL the games use? The rest of the article was implying so.--[[User talk:Glossy flame|Glossy flame]] 13:15, July 3, 2010 (UTC) | I thought this is the system which ALL the games use? The rest of the article was implying so.--[[User talk:Glossy flame|Glossy flame]] 13:15, July 3, 2010 (UTC) | ||
:No, it's not. In all previous games, damage from all weapons, including headshots, would carry over to an opponent's body if they overloaded the shield. So if your shield was low, a single high-caliber headshot would down your shield and lodge itself in your skull. In Reach, even if the shield is down to its last vestiges of energy, the disabling bullet won't carry ANY damage to your opponent when the shield breaks. Basically, there are no one-hit weapons besides the power weapons(sniper, shotty, explosives, etc). A bullet can only be used to harm the shields or the body. But not both. It can't blow through the shields and harm the person underneath in one shot like it could in Halo 1-3. Make sense?--[[User talk:Nerfherder1428|Nerfherder1428]] 22:37, July 3, 2010 (UTC) | |||